将杨辉三角中的每一个数
Cnr 都换成分数
(n+1)Cnr1,得到一个如图所示的分数三角形,称为莱布尼茨三角形.
\begin{array}{c}
&&&&&&$\displaystyle\frac{1}{1}$&&&&&&\\
&&&&&$\displaystyle\frac{1}{2}$&&$\displaystyle\frac{1}{2}$&&&&&\\
&&&&$\displaystyle\frac{1}{3}$&&$\displaystyle\frac{1}{6}$&&$\displaystyle\frac{1}{3}$&&&&\\
&&&$\displaystyle\frac{1}{4}$&&$\displaystyle\frac{1}{12}$&&$\displaystyle\frac{1}{12}$&&$\displaystyle\frac{1}{4}$&&&\\
&&$\displaystyle\frac{1}{5}$&&$\displaystyle\frac{1}{20}$&&$\displaystyle\frac{1}{30}$&&$\displaystyle\frac{1}{20}$&&$\displaystyle\frac{1}{5}$&&\\
&$\displaystyle\frac{1}{6}$&&$\displaystyle\frac{1}{30}$&&$\displaystyle\frac{1}{60}$&&$\displaystyle\frac{1}{60}$&&$\displaystyle\frac{1}{30}$&&$\displaystyle\frac{1}{6}$&\\
$\displaystyle\frac{1}{7}$&&$\displaystyle\frac{1}{42}$&&$\displaystyle\frac{1}{105}$&&$\displaystyle\frac{1}{140}$&&$\displaystyle\frac{1}{105}$&&$\displaystyle\frac{1}{42}$&&$\displaystyle\frac{1}{7}$\\
\multicolumn{13}{c}{$\cdots\cdots$}
\end{array}
从莱布尼茨三角形可看出
(n+1)Cnr1+(n+1)Cnx1=nCn−1r1,其中
x=______,令
an=31+121+⋯+nCn−121+(n+1)Cn21,则
n→∞liman=______.