11多选题6★★★★☆
已知 ABC\triangle ABC 的面积为 14\frac{1}{4}, cos2A+cos2B+2sinC=2\cos 2A + \cos 2B + 2 \sin C = 2, cosAcosBsinC=14\cos A \cos B \sin C = \frac{1}{4}, 则 ( )
A.
sinC=sin2A+sin2B\sin C = \sin^2 A + \sin^2 B
B.
AB=2AB = \sqrt{2}
C.
sinA+sinB=62\sin A + \sin B = \frac{\sqrt{6}}{2}
D.
AC2+BC2=3AC^2 + BC^2 = 3
答案与解析

答案已隐藏